if HCF (16,y)=8 and LCM (16,y)=48 then the value of "y" is
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If lcm(a,b)=l, hcf(a,b)=h a*b=l*h 16*y=48×8 y=(48×8)/16 y=3×8 y=24.
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Here is your answer friend...
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Keep learning maths...
Its an awesome subject... ^_^
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