Math, asked by rpadihar660, 7 months ago

If HCF (16, y) = 8 and LCM (16, y) = 48, then the value of y is​

Answers

Answered by viperisbackagain
1

Question

If HCF (16, y) = 8 and LCM (16, y) = 48, then the value of y is

solution

given

HCF = 8

LCM = 48

1st number = 16

2nd number = y

by using formula

HCF x LCM = 1st number x 2nd number

so. 8 x 48 = 16 x y

y= 8 x 48 / 16

y = 2 x 12

y = 24

hope it helps

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