If HCF (253,440) = 11 & LCM (253,440) = 253 X R. Find the value of R
Answers
Answered by
173
If a, b are any two positive numbers
Their hcf(a,b)=h and lcm (a,b)=l then
a×b= h×l
Given
a=253,b=440
h=11
l=253×R
Therefore
h×l=a×b
11×253×R=253×440
R=(253×440)/(11×253)
R=40
Their hcf(a,b)=h and lcm (a,b)=l then
a×b= h×l
Given
a=253,b=440
h=11
l=253×R
Therefore
h×l=a×b
11×253×R=253×440
R=(253×440)/(11×253)
R=40
Answered by
46
Answer:
40
Step-by-step explanation:
We know,
HCF × LCM = PRODUCT OF THE NOS.
Therefore,
11×253×R=253×440
11×253×R/253×440
R=40
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