Question

If HCF(51,85) =2m-1 ,then find m.​

Answer 1

Step-by-step explanation:

simple

hcf of 51,85=?

GCF is the product of the factors that are common to each of the given numbers.

Prime factorization of 51 is 3 × 17

Prime factorization of 85 is 5 × 17

The occurrences of common prime factors of 51 and 85 is 17

Hence HCF(51, 85) = 17

so

17= 2m - 1

2m = 17+1

2m = 18

m = 18/2

m = 9

Answer 2

Answer:

HCF of (51,85)=17

17=2m-1

17+1=2m

18=2m

m=18/2

m=9