If HCF = (65, 117) = 65m- 117 then m is-
(a) 2
(b) -2
(c) 1
(d) 3
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First we need to find the HCF of 65 and 117..
65 = 5 × 13
117 = 3 × 3 × 13
HCF ( 65 and 117 ) = 13
But we know HCF of 65 and 117 = 65m - 117
So ,
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