Math, asked by pradipk602, 7 months ago

if HCF(65,117)= 65m-177n. Then find the values of m and n​

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Answered by Anonymous
3

Answer:

By Euclid's division algorithm 117 = 65x1 + 52. 65 = 52x1 + 13 52 = 13x4 + 0. Therefore 13 is the HCF (65, 117)

By Euclid's division algorithm 117 = 65x1 + 52.65 = 52x1 + 1352 = 13x4 + 0Therefore 13 is ... M=2,n=-1By euclid's division lemma do and find the hcf of 117 and 65 and we will be ...

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