Question

If HCF(a,b)=8 LCM(a,b)= 64 and a>b then find a.​

Answer 1

Answer:

HCF*LCM=ab

8×64=512=2^9

As HCF =8=2^3

2^9÷2^3=2^9-3 = 2^6= 64

And is 64

Hope it will help you

Answer 2

The value of a is 64.

Given:

HCF(a,b)=8

LCM(a,b)= 64

a>b

To Find:

The value of a.

Solution:

we know the formula, HCF(a,b) × LCM(a,b) = a×b

8×64 = a×b

a×b = 512

      = 2×2×2×2×2×2×2×2×2

HCF(a,b) = 8

               = 2×2×2

Since a > b, the value of b is 8.

a = 512/8

 = 64

Therefore, The value of a is 64.

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