if hcf and lcm are a 'and b" 6 and 36 respectly then a is 12 find b
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Given :-
- If HCF and LCM of " a " and " b " 6 and 36 respectively then a is 12
To find :-
- Find the value of " b "
Solution :-
- HCF of numbers = 6
- LCM of numbers = 36
- One of number (a) = 12
As we know that
→ LCM × HCF = Product of two numbers
→ LCM × HCF = a × b
Where " a " is the first number and " b " is second number
According to question
→ LCM × HCF = a × b
Substitute the values
→ 36 × 6 = 12 × b
→ 216 = 12b
→ b = 216/12
→ b = 18
Hence,
- Value of other number (b) = 18
Verification :-
- LCM × HCF = Product of two numbers
LHS = LCM × HCF
→ 36 × 6
→ 216
RHS = Product of two numbers
→ 12 × 18
→ 216
- Therefore, LHS = RHS verified
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