If hcf and lcm of two numbers are respectively (n-1) and( n^2-1)(n^2-4), then the product of two numbers
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Given : HCF of two numbers = n - 1
LCM = (n² - 1)(n² - 4)
To Find : product of two numbers
Solution:
Two number a , b
HCF (a , b) * LCM (a , b) = product of two numbers
HCF (a , b) = n - 1
LCM (a , b) = (n² - 1)(n² - 4)
product of two numbers = (n -1 ) (n² - 1)(n² - 4)
= n⁵ - n⁴- 5n³ + 5n² + 4n - 4
product of two numbers is n⁵ - n⁴- 5n³ + 5n² + 4n - 4
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