Question

if HCF of 210 and 55 is expressed in the form of 210×5_55y then value of y square is​

Answer 1

Answer:

$y^{2} = 361$

Step-by-step explanation:

Answer

Let us first find the HCFof 210 and 55.

Applying Euclids division lemma on 210 and 55, we get

210=55×3+45  

Since the remainder 45



=0. So, we now apply division lemma on the divisor 55 and the remainder 45 to get

55=45×1+10  

We consider the divisor 45 and the remainder 10 and apply division lemma to get

45=4×10+5  

We consider the divisor 10 and the remainder 5 and apply division lemma  to get  

10=5×2+0  

We observe that the remainder at this stage is zero. So, that last divisor i.e.  

5 is the HCF of 210 and 55.

∴5=210×5+55y

⇒55y=5−210×5=5−1050

⇒55y=−1045

⇒y=  

55

−1045

​  

=−19

y^2 = -19*-19 = 361