if HCF of 210 and 55 is expressed in the form of 210×5_55y then value of y square is
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Let us first find the HCFof 210 and 55.
Applying Euclids division lemma on 210 and 55, we get
210=55×3+45
Since the remainder 45
=0. So, we now apply division lemma on the divisor 55 and the remainder 45 to get
55=45×1+10
We consider the divisor 45 and the remainder 10 and apply division lemma to get
45=4×10+5
We consider the divisor 10 and the remainder 5 and apply division lemma to get
10=5×2+0
We observe that the remainder at this stage is zero. So, that last divisor i.e.
5 is the HCF of 210 and 55.
∴5=210×5+55y
⇒55y=5−210×5=5−1050
⇒55y=−1045
⇒y=
55
−1045
=−19
y^2 = -19*-19 = 361
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