Question

if hcf of 210 and 55 is expressible in form 210*5+55y find y

Answer 1

Answer:

Step-by-step explanation:

210=55x3+45

55=45x1+10

45=10x4+5

10=5x2+0

HCF =5

210x5+55y=5

1050+55y=5

55y=1045

y=1045/55=19

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Answer 2

Hey Ma8 ,

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HCF of 210 and 55 is 5

according to the question

210 × 5 + 55Y = HCF of 210 and 55

210 × 5 + 55Y = 5

1050 + 55Y = 5

Y = 5 - 1050 ÷ 55

Y = 1045 ÷ 55

Y = 19

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