Question

IF HCF of 210 and 55 is expressible in the form
210 x5-55x find the value of x.​

Answer 1

Answer:

210 = 2*5*3*7

55 = 5*11

HCF = 5

210*5 - 55x = 5

1050 - 55x = 5

1050 - 5 = 55x

x = 19