If hcf of 210 and 55 is expressible in the form 210a+55b the find the value of a and b
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Answer:
210 = 55 × 3 + 45
55 = 45 × 1 + 10
45 = 10 × 4 + 5
10 = 5 × 2 + 0
HCF = 5
5 = 45 - 10(4)
5 = 45 - (55 - 45(1))4
5 = 210 - 55(3) - 55(4) + 210(4) - 55(7)
5 = 210(5) + 55(-10)
a = 5
b = -10
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