If hcf of 210 and 55 is of the form 210(5)+55y, than find y
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Hcf is 5
5=210*5+55y
5=1055+55y
-1050=55y
-1050÷55=y
-19=y
5=210*5+55y
5=1055+55y
-1050=55y
-1050÷55=y
-19=y
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