Question

If HCF of 408 and 1032 is expressible in the form 1032m - 408 x 5, find m

Answer 1

408 = (2^3)*3*17
1032= (2^3)*3*43

Therefore HCF = (2^3 )*3= 24

1032m - 408 x 5=24
1032m = 408*5 + 24 = 2040 +24= 2064
m = 2064/1032 = 2

therefore m= 2

Answer 2

Answer:

first find out the hcf

1032=408×2 + 216

408=216×1 + 192

216=192×1 + 24

192=24×8 + 0

so, now since the remainder has come zero 

so the hcf will be 24

now if we put hcf=1032-408×5

1032m-408×5=24

1032m-2040=24

1032m=24+2040⇒2064

m=2064÷1032⇒2

2 is the value of m.

I hope it is helpful