If HCF of 408 and 1032 is expressible in the form of 1032m-408×5,find m
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◆Ekansh Nimbalkar◆
hello friend here is your required answer
hello friend here is your required answer
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You can find the HCF of 408 and 1032 by Long division method or by Euclid division Algorithm.
I'm doing it by Euclid's
1032 > 408
1032 = 408 x 2 + 216
408 = 216 x 1 + 192
216 = 192 x 1 + 24
192 = 24 x 8 +0
The divisor is the HCF i.e 24
Now write this in reverse.
24 = 216 - 192 x 1
24 = 216 - (408 - 216 x 1)
24 = 2 x 216 - 408
24 = 2 x ( 1032 - 408 x 2) - 408
24 = 1032 x 2 - 408 x 5
1032m = 1032 x 2
m = 2
Required value of m is 2
Hope This Helps You!
I'm doing it by Euclid's
1032 > 408
1032 = 408 x 2 + 216
408 = 216 x 1 + 192
216 = 192 x 1 + 24
192 = 24 x 8 +0
The divisor is the HCF i.e 24
Now write this in reverse.
24 = 216 - 192 x 1
24 = 216 - (408 - 216 x 1)
24 = 2 x 216 - 408
24 = 2 x ( 1032 - 408 x 2) - 408
24 = 1032 x 2 - 408 x 5
1032m = 1032 x 2
m = 2
Required value of m is 2
Hope This Helps You!
99EkanshNimbalkar:
thanks for certification
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