if HCF of 45 and 27 is d and value of d is 45x + 27 y, then find value of x and y
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Answered by
5
by euclid division lemma
45=27×1+18 equation2
27=18×1+9 equation 1
18=9×2+0
now hcf is 9 so d is 9
from 1
27-18×1=9
from 2
27-(45-27×1)×1=9
27-45+27=9
27×2+45×(-1)=9
27y+45x=9
where x=-1 and y=2
hope it will help you
45=27×1+18 equation2
27=18×1+9 equation 1
18=9×2+0
now hcf is 9 so d is 9
from 1
27-18×1=9
from 2
27-(45-27×1)×1=9
27-45+27=9
27×2+45×(-1)=9
27y+45x=9
where x=-1 and y=2
hope it will help you
jvd:
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Answered by
0
Answer:
x=2 & y=-1
Step-by-step explanation:
By euclid division lemma
45=27×1+18 equation2
27=18×1+9 equation 1
18=9×2+0
now hcf is 9 so d is 9
from 1
27-18×1=9
from 2
27-(45-27×1)×1=9
27-45+27=9
27×2+45×(-1)=9
27y+45x=9
∴ x=-1 and y=2
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