if HCF of 57 and 117 is expressible in the form of 65 M - 117 find the value of m
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57 = 3×19
117 = 3×3×13
HCF = 3
Given,
HCF = 65m - 117
3 = 65m -117
3+117 = 65m
120 = 65m
m = 120/65
If you have any doubt you can also check it.
HCF = 65×m -117
= 65×120/65 -117
= 120-117 [ 65 cancels with 65]
= 3 = HCF
Hence m = 120/65
If you satisfied mark it brainliest.
117 = 3×3×13
HCF = 3
Given,
HCF = 65m - 117
3 = 65m -117
3+117 = 65m
120 = 65m
m = 120/65
If you have any doubt you can also check it.
HCF = 65×m -117
= 65×120/65 -117
= 120-117 [ 65 cancels with 65]
= 3 = HCF
Hence m = 120/65
If you satisfied mark it brainliest.
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