If HCF of 65 and 117 is expressible in the form 65n-117. Find the value of n?
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We know,
65 = 5 * 13
117 = 3 * 3 * 13
So, H. C. F = 13
Given, H. C. F = 65n - 117
13 = 65n - 117
13 + 117 = 65n
130 / 65 = n
2 = n
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