Question

If hcf of 65 and 117 is expressible in the form 65n-117 then find the value of n

Answer 1

65n-117=65×117

then you will find the answer

Answer 2

HEY MATE

find the HCF of 65 and 117,

117 = 1×65 + 52  

65 = 1× 52 + 13

52 = 4 ×13 + 0

∴ HCF of 65 and 117 is 13.

65n - 117 = 13

65n = 117+13 = 130

∴ n=130/65 = 2

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