Question

if HCF of 65 and 117 is expressible in the form of 65 and - 117 then find the value of n​

Answer 1

${\bold{\red{Solution ✍}}}$

 find the HCF of 65 and 117,

117 = 1×65 + 52

65 = 1× 52 + 13

∴ HCF of 65 and 117 is 13.

65n - 117 = 13

65n = 117+13 = 130

∴n =130/65 = 2

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Answer 2

Step-by-step explanation:

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