If hcf of 65 and 117 is expressible in the form of 65^ m - 117 then find the value of m
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in this question find the H.C.F of 65 and 117
117=65*1+52
65=52*1+13
52=13*4+0
hence hcf is 13
as the hcf is reprensted as 65m-117
so 65m-117=13
65m=130
m=2
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