Math, asked by mahikas2007, 2 months ago

If hcf of 96 and 404 is 4 is expressible in the form 404m+ 96n such that m = 5, then find the value of n?

Answers

Answered by abikuttymayil005
1

Answer:

u r answer is below

Step-by-step explanation:

very simple

just add and subract operations

add the 404  and  96 subract the 5 on aswer the valuve comes thats only a ans

Answered by 14silicariverrosabel
2

Answer:

-21

Step-by-step explanation:

In order to find answer the following steps have to be followed

1 Find Hcf of 404 and 96

1 Find Hcf of 404 and 962 form equation with given data

1 Find Hcf of 404 and 962 form equation with given data3 solve equation

Hcf of 404 and 96 is 4

404=96×4+20

96=20×4+16

20=16×1+4

16=4×4+0

(by Euclid's division algorithm)

we are given that

Hcf=404m+96n (substitute value of m)

Hcf=404(5)+96n (Hcf is 4)

4= 2020+96n

96n=4-2020

n= 4-2020/96

n=-21

hope this helps

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