if HCF of number 408 and 103 is expressed in form of 1032x-408×5 then find the value of x
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Answer:
408=2×2×2×3×17
1032=2×2×2×3×43
Hence, HCF=2×2×2×3=24
Now, 1032x−408×5=24⇒1032x=2064⇒x=2
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