if hcf of two numbers 35 and 45 is 5 and lcm is 63×a find the value of a
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HCF*LCM = product of both numbers.
5*63*a = 35*45
a = 35 * 45 / 5*63
a = 5
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let a and b are numbers, then
a×b=LCM×HCF= 630×9
GIVEN
a+b=153
Now
(a-b)^2= (a+b)^2 -4ab= 153^2–4×630×9=729
So,
(a-b)= √729=27
So the difference is 27
a×b=LCM×HCF= 630×9
GIVEN
a+b=153
Now
(a-b)^2= (a+b)^2 -4ab= 153^2–4×630×9=729
So,
(a-b)= √729=27
So the difference is 27
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