Question

If HCF of two numbers is 42 and their LCM is 1260, and one of the number is 210, find the other.​

Answer 1

Answer:

Let the required number be x.

Given, HCF(x,210)=42 & LCM(x,210)=1260

Since, HCF(a,b)×LCM(a,b)=a×b

Therefore, HCF(x,210)×LCM(x,210)=210x

42 × 1260 = 210x

$x = (42 \times 126) \div 21$

$x = 42 \times 6$

$x = 252$

Answer 2

Answer:

x = 252

Step-by-step explanation:

HCF(x , 210) = 42

LCM(x , 210) = 1260

LCM(x , 210) = x × 210

HCF(x , 210)

1260 = x × 210

42

1260 × 42 = x × 210

x = 1260 × 42

210

x = 126 × 2

1

x = 252

Hope it helps you....