if hcf of (x,y)=1, then hcf of (x-y;x+y)=______
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HCF(x,y)=1
x-y;x+y
let x-y=a
x+y=b
HCF(a,b)=1-y+x(as x is substrates by y and x is added to x)
HCF(x-y;x+y)=1+x-y
x-y;x+y
let x-y=a
x+y=b
HCF(a,b)=1-y+x(as x is substrates by y and x is added to x)
HCF(x-y;x+y)=1+x-y
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