If hcf of x³-27 and x³+4x²+12x+k is a quadretic polynomial find k
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x³ = (3)³
x = 3
x³+4x²+12x+k
(3)³ + 4(3)² + 12(3) = ⁻ k
27 + 36 + 36 = ⁻ k
k = ⁻ 99
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