if HCL of two number is 12 and LCH of the same is 72 find the sum of the reciprocal of the two number if the sum of two number is 60
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Step-by-step explanation:
Let the two numbers be x and y.
We know that.. product of two numbers = HCFx LCM.
Therefore XY= 12 x 72= 864….(1)
According to given condition, their sum is 60
Therefore x+y = 60……….(2)
We know that
(x-y)² =(x+y)² -4xy
Substitute values from 1 & 2
(X-y)² = 3600–4x864=144
X-Y =√144= 12…(3)
By solving 2 and 3
We get x=36 and y=24.
1/36 + 1/ 24 = 5 / 72
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Answer:
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Step-by-step explanation:
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