if he intercept made on the line y=mx by the lines x=2 and x=5 is less than 5 then range of m
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A/Q intercept by x= 2 and x= 5 is less than 5
intersection of y= mx and x=2 and x=5
A ( 2 , 2m) and B( 5 , 5m)
so √ (5-2)² + (5m - 2m)² < 5 distance formula
squaring both sides
⇒ 9 + 9m² < 25 ⇒ 9m² < 16 ⇒ m² < 16/9
-4/3 < m < 4/3
hope my ans to be correct ..........doubts ,,,,,,,enquire?
intersection of y= mx and x=2 and x=5
A ( 2 , 2m) and B( 5 , 5m)
so √ (5-2)² + (5m - 2m)² < 5 distance formula
squaring both sides
⇒ 9 + 9m² < 25 ⇒ 9m² < 16 ⇒ m² < 16/9
-4/3 < m < 4/3
hope my ans to be correct ..........doubts ,,,,,,,enquire?
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