Question

If heat of combustion of ethylene is 1411 KJ when a certain amount of ethylene was burnt 6226 KJ.heat was evolved. Then the volume of O2
(at S.T.P.) that entered into the reaction is :-

(1) 296.5 ml
(2) 296.5 litre
(3) 6226 22.4 litre
(4) 22.4 litre​

Answer 1

Answer:

Hi mate....!!

Here is your answer

Explanation:

C2H4 + 3O2 -------> 2 CO2 + 2 H2O

C2H4 + 3O2 -------> 2 CO2 + 2 H2OMoles of O2 reacted = (6226/1411) x 3

C2H4 + 3O2 -------> 2 CO2 + 2 H2OMoles of O2 reacted = (6226/1411) x 3Volume of O2 entered at STP = (6226/1411) x 3 x 224 = 296.5 li

Hope you understand

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Answer 2

Answer:

(1)296.5 l is the right answer.

Explanation:

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