If heating 10g of Calcium Carbonate produces 4.4g of Carbon Dioxide
and 5.6g of Calcium Oxide, show that these observations are in
agreement with law of conservation of mass.
please answer
Answers
Given:-
→Mass of Calcium carbonate that
was heated = 10g
→Mass of Carbon dioxide
produced = 4.4g
→Mass of Calcium oxide produced = 5.6g
To show:-
→The above observations are in agreement with Law of Conservation of mass.
Solution:-
In the above observation, reactant is :-
•Calcium carbonate
In the above observation,products are:-
•Carbon-dioxide
•Calcium-Oxide
Now,according to Law Of Conservation of mass,we know that:-
Total mass of reactants=Total mass of products
Here,mass of reactant i.e. Calcium Carbonate is 10g.
Total mass of products:-
= (4.4 + 5.6) g
= 10g
As we can see that the mass of reactant as well as mass of products is 10g.
Thus,the above observations are in agreement with the Law of Conservation of mass.
The law of conservation of mass states that,
“In a chemical reaction, the mass of reactants and the mass of products remain constant.”
We are given that,
Mass of reactant = 10 g (CaCO3)
Also, mass of product = 4.4 g (CO2) + 5.6 g (CaO)
⇒ Mass of product = 10 g.
∴ The mass before reaction is same as after reaction. Or, the observation is in agreement with the law of conservation of mass.
More:-
When is the law of conservation of mass violated?
Whenever a certain mass is converted into energy (which has no mass), for e.g., burning of wood, the law is violated.
Moreover, in the formula, e = mc², Einstein declared that mass and energy are convertible. This violated the law. (Relationship between Energy and Mass, e = energy, c = speed of light in vaccum, m = mass).