if height of cuboidal box is increased by 50 percent find percent increase in its 1.lsa and volume?
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Answered by
1
Answer:
Let the original side be a then
Original surface area S=6a
2
When side is increased by 50%, side becomes
2
3
a then
Surface area s=
2
27
a
2
Hence,
Surface area is increases by x=
6a
2
2
27
a
2
−6a
2
×100=125%
This is the required solution.
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