Question

If [HO−]=6.0×10−10⋅mol⋅L−1, what is pH for this solution?

Answer 1

Hi,,,

[H3O] = Kw÷ [OH]

[H3O]= 1×10^-14÷6×10^-10= 1.67×10^-5

pH= -log [H3O]

pH= -log 1.67×10^-5= 4.7

Hope the answer is helpful