if hydrogen and oxygen combine in the ratio of 1 ratio 8 by mass respectively to form water molecule explain how many moles of water will be formed using 10 moles of hydrogen gas and 5 moles of Oxygen gas
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10 moles of hydrogen=10*avagardo no.
5 moles of oxygen=5*avagardo no.
let avagardo no. be x
10x+5x=5(2x+x)=water
no. of molecules of water in above equation =5(2x+x)/3 (since one molecule of water contains 3 atoms)
we know that number of moles=given no. of particles/avagardo number
number of moles of water=5(2x+x)/3/x 9we have taken x=avagrado no.)
=5(2x+x)/3x
=5(3x)/3x
=5
no. of moles of water is 5
5 moles of oxygen=5*avagardo no.
let avagardo no. be x
10x+5x=5(2x+x)=water
no. of molecules of water in above equation =5(2x+x)/3 (since one molecule of water contains 3 atoms)
we know that number of moles=given no. of particles/avagardo number
number of moles of water=5(2x+x)/3/x 9we have taken x=avagrado no.)
=5(2x+x)/3x
=5(3x)/3x
=5
no. of moles of water is 5
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