Question

If hydrogen atom is excited by giving 8.4 ev energy then number of emitted spectrum lines will be:

Answer 1

Answer:

8.4 ev

Explanation:

E � 1/n2

For n=1, E = 13.6 eV

Thus energy absorbed =13.6 (1 - (1 / n2) eV., where n =1 to �

For n=2, E = 13.6(1 - (1 / 22) = 10.2

This is the lowest energy state possible for emission of spectral lines.

Thus the energy absorbed should always be between 10.2 and 13.6 eV

Hence , no emission takes place when hydrogen atom is excited by giving 8.4eV.