Question

If hydrogen atom is excited by giving 8.4 ev energy then the no of spectral lines emitted will be

Answer 1

E � 1/n2

For n=1, E = 13.6 eV

Thus energy absorbed =13.6 (1 - (1 / n2) eV., where n =1 to �

For n=2, E = 13.6(1 - (1 / 22) = 10.2

This is the lowest energy state possible for emission of spectral lines.

Thus the energy absorbed should always be between 10.2 and 13.6 eV

Hence , no emission takes place when hydrogen atom is excited by giving 8.4eV.

Answer 2

Answer:

E ? 1/n²

For n=1,E=13.6eV

Thus energy absorbed=13.6(1-(1/n²)eV.

where n=1 to ?

For n=2,E=13.6-(1/2²)=10.2

This the lowest energy state possible for emission of spectral lines.

Thus the energy absorbed shld always be between 10.2 and 13.6eV.

Hence ,no emission takes place when hydrogen atom is exited by giving 8.4eV.