Question

If hypotenus is 8√2, then find other two sides of triangle.​

Answer 1

Answer:

BRUH!

The hypotenuse is 8√2.

Using Pythagoras theorem:

x²+y²=(8√2)²

x²+y²=64×2

x²+y²=128.

Now, just assume values...

Let's assume x=10

10²+y²=128

y²=128-100

y²=28

y=√28units.

Thus, x=10units, y=√28units.

Check it using the same theorem:

10²+(√28)² =128

100+28=128

128=128.

Verified ✓.

HOPE THIS HELPS :D