If hypotenuse of a right triangle is 4 times the smallest side. The third side is root735. Find the hypotenuse and the smallest side
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let the smallest side = x
hypotenuse= 4x
3 side= √735
Pythagoras theorem
h^2= p^2+b^2
4x^2=√735^2+ x^2
16x^2= 735+x^2
16x^2-x^2= 735
15x^2= 735
x^2= 735/15
x^2= 49
x= √49
x= 7
so,
Smallest side= 7cm
hypotenuse= 4×7= 28cm
hypotenuse= 4x
3 side= √735
Pythagoras theorem
h^2= p^2+b^2
4x^2=√735^2+ x^2
16x^2= 735+x^2
16x^2-x^2= 735
15x^2= 735
x^2= 735/15
x^2= 49
x= √49
x= 7
so,
Smallest side= 7cm
hypotenuse= 4×7= 28cm
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