if hyptanuse is 9 ,base is 6 then find perpendicular of right angled triangle
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h=9
b=6
p2=h2-b2
=81-36
=√45
=6.70
b=6
p2=h2-b2
=81-36
=√45
=6.70
Answered by
0
Heya !!!
Here is your answer !!
______________________________
h = 9
b = 6
By pythargorus theorem,
p^2 = h^2 - b^2
=> p^2 = (9)^2 - (6)^2
=> p^2 = 81 - 36
=> p^2 = 45
=> p = 3 root 5
_______________________________
# Gudiya
Hope it helps !! ☺✌
Here is your answer !!
______________________________
h = 9
b = 6
By pythargorus theorem,
p^2 = h^2 - b^2
=> p^2 = (9)^2 - (6)^2
=> p^2 = 81 - 36
=> p^2 = 45
=> p = 3 root 5
_______________________________
# Gudiya
Hope it helps !! ☺✌
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