Question

if I=√-1 find the value of (3+2i)(3-2i)​

Answer 1

Answer:

3+2(_1) 3_2(_1)=9_6i+6i_4ipower 2

9+4=13

Answer 2

Answer:

Value is 5.

Step-by-step explanation:

Given :

• i = $\sqrt{- 1}$

To Find :

• Value of (3 + 2i)(3 - 2i)

Solution :

$(3 + 2i)(3 - 2i) \qquad \sf \{ \: Put \: value \: of \: i \: \} \\ \\ \implies(3 + 2 \times \sqrt{- 1})(3 - 2 \times \sqrt{- 1}) \qquad \sf \{ \: Applying \: Identity : (a + b)(a - b) = a^2 - b^2 \: \} \\ \\ \implies {3}^{2} + {(2 \times \sqrt{- 1})}^{2} \\ \\ \implies9 + 4 \times - 1 \\ \\ \implies 9 - 4 \\ \\ \implies 5$