Question

if i^2=-1 then find (1+i)^10​

Answer 1

Answer:

32i

step- by -step explanation

given

i^2=-1

1+i^2=0

find

=(1+i)^10

=((1+i)^2)×((1+i)^2)×((1+i)^2)×((1+i)^2)×((1+i)^2)

=(1^2+i^2+2i)(1^2+i^2+2i)(1^2+i^2+2i)(1^2+i^2+2i)(1^2+i^2+2i)

=(0+2i)(0+2i)(0+2i)(0+2i)(0+2i)

=2i×2i×2i×2i×2i

=32i