Question

If Ā=i+2j + 3k , B=-i+ j + 4k and C = 3i - 3j - 12k , then find the angle between the vectors
(A + B + Č) and (AxB) in degrees.​

Answer 1

Explanation:

Hope it is helpful for you..

Answer 2

Answer:

θ=90°

Explanation:

(A+B+C)=P

P= (1-1+3)i + (2+1-3)j +(3+4-12)k

P = 3i-5k

(A×B)= Q

Q= 5i-7j+3k    (After cross multiplying)

P.Q= (3i-5k).(5i-7j+3k) = (15-15) = 0

P·Q=PQcosθ

cosθ=$\frac{P.Q}{PQ}$

cosθ=$\frac{0}{\sqrt{9+25}\sqrt{25+49+9} } }$

cosθ = 0

θ=90°