If (i^4+3i)a+(i-1)b+5i^3=0 find a and b
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where i^2=-1,i^3=-i
given (i^4+3i)a+(i-1)b+5i^3=0
(1+3i)a+bi-b-5=0
a+3ai+bi-b-5=0
a-b+(3a-b)i=5
a-b=5. -(1) ,(3a-b)i=5 -(2)
a=5+b
sub a=5+b in equation (2)
(3(5+b)-b) i=5
(15+3b-b) i=5
(15-2b)i=5
15i-2bi=5
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