Math, asked by DAJ2003, 1 year ago

if I add 1 to each of the two given numbers then their ratio is 1:2. If I subtract 5 from each of the numbers, the ratio is 5:11. Find the numbers by elimination meth.


DAJ2003: Please saniya can you help me...

Answers

Answered by Panzer786
41
Hiii friend,



Let the two numbers be X and Y.

1 is added to each Number then the numbers becomes X+1 and Y+1

According to question,

X + 1/Y+1 = 1/2

2(X+1) = 1(Y+1)

2X + 2 = Y +1

2X -Y = 1-2

2X - Y = -1---------(1)


5 is subtracted to each NUMBERS then the numbers becomes (X-5) and (Y-5).

According to question,

(X-5)/(Y-5) = 5/11

11(X-5) = 5(Y-5)


11X - 55 = 5Y - 25


11X - 5Y = -25+55

11X - 5Y = 30---------(2)

From equation (1) we get,

2X - Y = -1


2X = -1 + Y

X = -1+Y/2--------(3)


Putting the value of X in equation (2)

11X - 5Y = 30


11 × (-1+Y/2) - 5Y = 30


-11 + 11Y/2 - 5Y = 30


-11+11Y - 10Y = 30 × 2


Y - 11 = 60

Y = 60+11

Y = 71


Putting the value of Y in equation (3)


X = -1+Y/2 => -1 + 71/2 => 70/2


X = 35


Hence,


Number are 71 and 35.


HOPE IT WILL HELP YOU...... :-)

DAJ2003: thank you again saniya
Answered by tanvigupta426
2

Answer:

The number are 71 and 35.

Step-by-step explanation:

Let the two numbers be X and Y.

1 is added to each Number then the numbers become X+1 and Y+1

According to the question,

Step 1

X + 1/Y+1 = 1/2

2(X+1) = 1(Y+1)

2X + 2 = Y +1

2X -Y = 1-2

2X - Y = -1---------(1)

5 is subtracted from each number then the numbers become (X-5) and (Y-5).

According to the question

Step 2

(X-5)/(Y-5) = 5/11

11(X-5) = 5(Y-5)

11X - 55 = 5Y - 2

11X - 5Y = -25+5

11X - 5Y = 30---------(2

From equation (1) we get,

2X - Y = -

2X = -1 + Y

X = -1+Y/2--------(3)

Putting the value of X in equation (2)

Step 3

11X - 5Y = 30

11 × (-1+Y/2) - 5Y = 30

-11 + 11Y/2 - 5Y = 30

-11+11Y - 10Y = 30 × 2

Y - 11 = 60

Y = 60+11

Y = 71

Step 3

Putting the value of Y in equation (3)

X = -1+Y/2 => -1 + 71/2 => 70/2

X = 35

Hence,

The number are 71 and 35.

#SPJ2

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