if i are j unit vectors along mutually perpendicular directions then the magnitude of i - j is
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Answer: since î and j^ are mutually perpendicular to wash other then angle between both the vectors will be 90°
Now î= 1( because it is unit vector )
And j^ = -1
Now |[î-j^]|= √(1)²+(-1)²+ cos90°
= √ 1+1+0. (Because cos90°=0)
= √2
Hence, magnitude of î-j^ is √2
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