if i ask you that 0=1&(-1) and it is true then what will be your answer?
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If a & b are integers then I can type as a = b+1
a = b+1 ..............................................{multiply both side with (a-b)}
(a-b)*a = (a-b)*(b+1) .......................... {I will get}
a^2 -ab =ab + a - b^2 - b...................{now subtract 'a' with LHS & 'b' with RHS}
a^2 - ab - a = ab + a - a - b^2 - b
a(a - b - 1) = b(a - b -1) ........................{now (a - b - 1) = (a - b - 1) get canceled }
a = b ...................................................{ a = b+1}
b + 1 = b
1 = b - b
1 = 0 or 1 = 0 ......................................{now add - at both sides)
-1 = -0 ................................................{ -0 = 0}
-1 = 0 or 0 = -1
I THINK THIS ANSWER MAY SATISFY YOU
a = b+1 ..............................................{multiply both side with (a-b)}
(a-b)*a = (a-b)*(b+1) .......................... {I will get}
a^2 -ab =ab + a - b^2 - b...................{now subtract 'a' with LHS & 'b' with RHS}
a^2 - ab - a = ab + a - a - b^2 - b
a(a - b - 1) = b(a - b -1) ........................{now (a - b - 1) = (a - b - 1) get canceled }
a = b ...................................................{ a = b+1}
b + 1 = b
1 = b - b
1 = 0 or 1 = 0 ......................................{now add - at both sides)
-1 = -0 ................................................{ -0 = 0}
-1 = 0 or 0 = -1
I THINK THIS ANSWER MAY SATISFY YOU
deb5:
Now tell me about infinity may be equal to 1 &-1
omg that really critical
I don't think so
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