Chemistry, asked by harshadeep3612gogoi, 11 months ago

If I have 15.4 mg of Ge(Germanium) , how many atoms of Ge am I dealing with ?
[Ge = 72.64 u]

Answers

Answered by balaji203858
1

Explanation:

no. of moles = mass / gram m. wt

= 15.4/72.64

=0.212

no of atoms = no. of moles×avagadro number

= 0.212× 6.023×10^²³

= 1.2768× 10^²³

Answered by hayarasheed
1

Answer:

1.2767 × 10^20 atoms of Ge

Explanation:

To find no. of moles,

Number of moles= Given mass ÷ Molecular mass

= 15.4 × 10^-3÷ 72.64

=2.12×10^-4

Number of atoms = Number of moles× Avogadro's number

= 2.12×10^-4 × 6.022×10^23

= 1.2767× 10^20 atoms

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