if i increase the length 1% what will be the resistance change
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if, length= l and resistance (R) =pl/A=p(l^2)/V
Then , increase in length = l*20/100
l'= l+(l/5)
l'=6l/5
Final resistance = p( l'^2)/V
R'=p *36(l^2)/25V
R'=(36/25)R
Increase in resistance (%) ={( R'-R) /R}*100
=11R*100/25R %
=44%
Then , increase in length = l*20/100
l'= l+(l/5)
l'=6l/5
Final resistance = p( l'^2)/V
R'=p *36(l^2)/25V
R'=(36/25)R
Increase in resistance (%) ={( R'-R) /R}*100
=11R*100/25R %
=44%
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