Question

If I is a zero
of the polynomials
p(x) = ax^2-3(a-2) then find
the
value of
а.


​

Answer 1

Answer:

a = 3

Step-by-step explanation:

Substitute 1 in place of x

p(x) = ax²-3(a-2)

p(x) = a-3(a-2) =0

a-3(a-2) =0

a-3a+6 = 0

-2a = -6

a = 3

Answer 2

Answer:

Answer

Given: p(x)=ax2−3(a−1)x−1

One of the zero =1

As one of the zeroes is 1, substituting it in the polynomial

⇒p(1)=0=a−3(a−1)−1

⇒0=−2a+3−1

⇒a=1

Step-by-step explanation:

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